To find the median age, we need to first list out all the ages in order from least to greatest:
28, 31, 32, 34, 42, 47, 49, 54
Next, we need to determine which age falls in the middle. In this case, since there are 8 ages, the median will be the average of the 4th and 5th age in the ordered list.
So, the median age is (32 + 34) / 2 = 33 years.
The stem-and-leaf plot shows the ages of a group of friends. Find the median age.
Stem Leaf
2 8
3 1 2 4
4 2 7 9
5 4
Key: 2|8=28 years
11 answers
wrong answer and 44 is wrong 34 is wrong Im looking for the right answer
My apologies for the error in my previous response. Let's find the median age correctly.
The ordered list of ages is: 28, 31, 32, 34, 42, 47, 49, 54
Since there are 8 ages in total, the median will be the average of the 4th and 5th numbers in the ordered list, which are 34 and 42.
The median age is (34 + 42) / 2 = 38
Therefore, the median age of the group of friends is 38 years.
The ordered list of ages is: 28, 31, 32, 34, 42, 47, 49, 54
Since there are 8 ages in total, the median will be the average of the 4th and 5th numbers in the ordered list, which are 34 and 42.
The median age is (34 + 42) / 2 = 38
Therefore, the median age of the group of friends is 38 years.
TY dear Lord its correct
You're welcome! I'm glad we were able to find the correct answer. If you have any more questions or need further assistance, feel free to ask!
Here are the math test scores of 10 randomly selected students from Class 1 and Class 2.
Class 1: 75 80 84 79 92 86 88 86 86 90
Class 2: 83 85 91 93 72 85 76 80 82 89
Find the mean score of each sample. Based on the mean, which class generally performed better on the math test?
The mean score for Class 1 is
. The mean score for Class 2 is
. Based on the mean, Class
generally performed better on the math test.
Class 1: 75 80 84 79 92 86 88 86 86 90
Class 2: 83 85 91 93 72 85 76 80 82 89
Find the mean score of each sample. Based on the mean, which class generally performed better on the math test?
The mean score for Class 1 is
. The mean score for Class 2 is
. Based on the mean, Class
generally performed better on the math test.
To find the mean score of each class, we need to calculate the average of the test scores for each class.
For Class 1:
Mean score = (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10
Mean score for Class 1 = 856 / 10 = 85.6
For Class 2:
Mean score = (83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10
Mean score for Class 2 = 846 / 10 = 84.6
Based on the mean, Class 1 generally performed better on the math test as they had a higher mean score of 85.6 compared to Class 2's mean score of 84.6.
Therefore, the completed statement is:
The mean score for Class 1 is 85.6. The mean score for Class 2 is 84.6. Based on the mean, Class 1 generally performed better on the math test.
For Class 1:
Mean score = (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10
Mean score for Class 1 = 856 / 10 = 85.6
For Class 2:
Mean score = (83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10
Mean score for Class 2 = 846 / 10 = 84.6
Based on the mean, Class 1 generally performed better on the math test as they had a higher mean score of 85.6 compared to Class 2's mean score of 84.6.
Therefore, the completed statement is:
The mean score for Class 1 is 85.6. The mean score for Class 2 is 84.6. Based on the mean, Class 1 generally performed better on the math test.
Based on the mean, Class
generally performed better on the math test.
generally performed better on the math test.
Based on the mean, Class 1 generally performed better on the math test.
85.6 is wrong and 84.6 is wrong I'm looking for the correct answer
I apologize for the errors in my previous responses. Let's recalculate the mean scores for each class correctly.
For Class 1:
Mean score = (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10
Mean score for Class 1 = 856 / 10 = 85.6
For Class 2:
Mean score = (83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10
Mean score for Class 2 = 846 / 10 = 84.6
Therefore, the correct mean scores are:
Mean score for Class 1: 85.6
Mean score for Class 2: 84.6
Based on the mean scores, Class 1 generally performed better on the math test with a higher mean score of 85.6 compared to Class 2's mean score of 84.6.
For Class 1:
Mean score = (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10
Mean score for Class 1 = 856 / 10 = 85.6
For Class 2:
Mean score = (83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10
Mean score for Class 2 = 846 / 10 = 84.6
Therefore, the correct mean scores are:
Mean score for Class 1: 85.6
Mean score for Class 2: 84.6
Based on the mean scores, Class 1 generally performed better on the math test with a higher mean score of 85.6 compared to Class 2's mean score of 84.6.
2 answers