The correct method for finding the volume of a rectangular prism is:
V = length x width x height
So, V = 3 1/4 x 5 1/6 x 7 1/3
V = (13/4) x (31/6) x (22/3)
V = 4298/72
V = 59.6389
Therefore, the correct option is:
V = 3 1/4 x 5 1/6 x 7 1/3
Jamal needs to find the volume of a rectangular prism that has a height of 7 1/3 in., a length of 3 1/4 in., and a width of 5 1/6 in. Which option shows the correct method for solving this problem?(1 point) Responses V=713+314+516 upper V equals 7 Start Fraction 1 over 3 End Fraction plus 3 Start Fraction 1 over 4 End Fraction plus 5 Start Fraction 1 over 6 End Fraction V=713×314×516 upper V equals 7 Start Fraction 1 over 3 End Fraction times 3 Start Fraction 1 over 4 End Fraction times 5 Start Fraction 1 over 6 End Fraction V=314×516 upper V equals 3 Start Fraction 1 over 4 End Fraction times 5 Start Fraction 1 over 6 End Fraction V=7×3×5
11 answers
What is the volume of a rectangular prism that has a height of 10 1/2 in., a length of 6 2/3 in., and a width of 2 1/4 in.? Is it large enough to hold an item that has a height of 8 in., a length of 6 in., and a width of 2 in.?(1 point)
Responses
3,78024 in.3 and no, the item will not fit inside the prism.
Start Fraction 3,780 over 24 End Fraction in cubed and no, the item will not fit inside the prism.
160 in.3 and yes, the item should fit inside the prism.
160 in cubed and yes, the item should fit inside the prism.
15 in.3 and no, the item will not fit inside the prism.
15 in cubed and no, the item will not fit inside the prism.
15712 in.3 and yes, the item should fit inside the prism.
Responses
3,78024 in.3 and no, the item will not fit inside the prism.
Start Fraction 3,780 over 24 End Fraction in cubed and no, the item will not fit inside the prism.
160 in.3 and yes, the item should fit inside the prism.
160 in cubed and yes, the item should fit inside the prism.
15 in.3 and no, the item will not fit inside the prism.
15 in cubed and no, the item will not fit inside the prism.
15712 in.3 and yes, the item should fit inside the prism.
To find the volume of the rectangular prism, you would use the formula:
V = length x width x height
Given:
Length = 6 2/3 inches = 20/3 inches
Width = 2 1/4 inches = 9/4 inches
Height = 10 1/2 inches = 21/2 inches
V = (20/3) x (9/4) x (21/2) = 315 cubic inches
The volume of the rectangular prism is 315 cubic inches.
Now, to check if the item with dimensions 8 x 6 x 2 inches can fit inside this prism, we calculate its volume:
V = 8 x 6 x 2 = 96 cubic inches
Since 96 cubic inches is less than 315 cubic inches, the item should fit inside the prism.
Therefore, the correct answer is:
160 in cubed and yes, the item should fit inside the prism.
V = length x width x height
Given:
Length = 6 2/3 inches = 20/3 inches
Width = 2 1/4 inches = 9/4 inches
Height = 10 1/2 inches = 21/2 inches
V = (20/3) x (9/4) x (21/2) = 315 cubic inches
The volume of the rectangular prism is 315 cubic inches.
Now, to check if the item with dimensions 8 x 6 x 2 inches can fit inside this prism, we calculate its volume:
V = 8 x 6 x 2 = 96 cubic inches
Since 96 cubic inches is less than 315 cubic inches, the item should fit inside the prism.
Therefore, the correct answer is:
160 in cubed and yes, the item should fit inside the prism.
When applying the volume formula, what is the volume of a rectangular cereal box with a height of 3/4 ft., a length of 1/2 ft., and width of 1/2 ft.? Answer needs to be in fraction form.(1 point)
Responses
14ft.3
Start Fraction 1 over 4 end fraction ft cubed
58ft.3
Start Fraction 5 over 8 end fraction ft cubed
316ft.3
Start Fraction 3 over 16 end fraction ft cubed
38ft.3
Responses
14ft.3
Start Fraction 1 over 4 end fraction ft cubed
58ft.3
Start Fraction 5 over 8 end fraction ft cubed
316ft.3
Start Fraction 3 over 16 end fraction ft cubed
38ft.3
To find the volume of the rectangular cereal box, you would use the formula:
V = length x width x height
Given:
Length = 1/2 ft
Width = 1/2 ft
Height = 3/4 ft
V = (1/2) x (1/2) x (3/4)
V = 1/4 x 3/4 = 3/16
The volume of the rectangular cereal box is 3/16 cubic feet.
Therefore, the correct answer is:
3/16 ft cubed
V = length x width x height
Given:
Length = 1/2 ft
Width = 1/2 ft
Height = 3/4 ft
V = (1/2) x (1/2) x (3/4)
V = 1/4 x 3/4 = 3/16
The volume of the rectangular cereal box is 3/16 cubic feet.
Therefore, the correct answer is:
3/16 ft cubed
What is the volume of a moving truck with the following measurements: 9 9/10 ft. long, 6 1/10 ft. high, and 6 9/10 ft. wide? Apply the volume formula for a rectangular prism to solve. (1 point)
Responses
4166911,000ft.3
416 start fraction 691 over 1,000 end fraction ft cubed
6831100ft.3
68 start fraction 31 over 100 end fraction ft cubed
22910ft.3
22 start fraction 9 over 10 end fraction ft cubed
6914161,000ft.3
Responses
4166911,000ft.3
416 start fraction 691 over 1,000 end fraction ft cubed
6831100ft.3
68 start fraction 31 over 100 end fraction ft cubed
22910ft.3
22 start fraction 9 over 10 end fraction ft cubed
6914161,000ft.3
To find the volume of the moving truck, you would use the formula:
V = length x width x height
Given:
Length = 9 9/10 ft = 99/10 ft
Width = 6 9/10 ft = 69/10 ft
Height = 6 1/10 ft = 61/10 ft
V = (99/10) x (69/10) x (61/10)
V = 6,059/1000
V = 6.059 ft cubed
Therefore, the correct answer is:
416 start fraction 691 over 1000 end fraction ft cubed
V = length x width x height
Given:
Length = 9 9/10 ft = 99/10 ft
Width = 6 9/10 ft = 69/10 ft
Height = 6 1/10 ft = 61/10 ft
V = (99/10) x (69/10) x (61/10)
V = 6,059/1000
V = 6.059 ft cubed
Therefore, the correct answer is:
416 start fraction 691 over 1000 end fraction ft cubed
Applying the formula, what is the volume of a fish tank with the following dimensions: the length is 3 6 12 in., the width is 1 2 34 in., and the height is 1 8/12 in.?(1 point)
Responses
23578in.3
235 Start Fraction 7 over 8 end fraction in cubed
6634in.3
66 Start Fraction 3 over 4 end fraction in cubed
67514in.3
675 Start Fraction 1 over 4 end fraction in cubed
8,609716in.3
Responses
23578in.3
235 Start Fraction 7 over 8 end fraction in cubed
6634in.3
66 Start Fraction 3 over 4 end fraction in cubed
67514in.3
675 Start Fraction 1 over 4 end fraction in cubed
8,609716in.3
To find the volume of the fish tank, you would use the formula:
V = length x width x height
Given:
Length = 3 6/12 in = 42 in
Width = 1 2/34 in = 14 in
Height = 1 8/12 in = 18 in
V = 42 x 14 x 18 = 10584 in^3
Therefore, the correct answer is:
10584 in^3
V = length x width x height
Given:
Length = 3 6/12 in = 42 in
Width = 1 2/34 in = 14 in
Height = 1 8/12 in = 18 in
V = 42 x 14 x 18 = 10584 in^3
Therefore, the correct answer is:
10584 in^3
Applying the formula, what is the volume of a fish tank with the following dimensions: the length is 3 6/12 in., the width is 1 2/34 in., and the height is 1 8/12 in.?(1 point)
Responses
23578in.3
235 Start Fraction 7 over 8 end fraction in cubed
6634in.3
66 Start Fraction 3 over 4 end fraction in cubed
67514in.3
675 Start Fraction 1 over 4 end fraction in cubed
8,609716in.3
Responses
23578in.3
235 Start Fraction 7 over 8 end fraction in cubed
6634in.3
66 Start Fraction 3 over 4 end fraction in cubed
67514in.3
675 Start Fraction 1 over 4 end fraction in cubed
8,609716in.3
To find the volume of the fish tank with the given dimensions:
Length = 3 6/12 in = 3 + 6/12 in = 3.5 ft
Width = 1 2/34 in = 1 + 2/34 in = 1.0588 ft (approx.)
Height = 1 8/12 in = 1 + 8/12 in = 1.6667 ft (approx.)
V = length x width x height
V = 3.5 x 1.0588 x 1.6667
V ≈ 6.6668 ft^3
Therefore, the correct answer is:
6,6668 ft^3
Length = 3 6/12 in = 3 + 6/12 in = 3.5 ft
Width = 1 2/34 in = 1 + 2/34 in = 1.0588 ft (approx.)
Height = 1 8/12 in = 1 + 8/12 in = 1.6667 ft (approx.)
V = length x width x height
V = 3.5 x 1.0588 x 1.6667
V ≈ 6.6668 ft^3
Therefore, the correct answer is:
6,6668 ft^3