A student drops a ball from the roof of a tall building; The ball takes 6.0 s to reach the ground. The speed of the ball just before hitting the ground is:

1 answer

The speed of the ball just before hitting the ground can be calculated using the equation for free fall:

v = gt

where v is the speed of the ball just before it hits the ground, g is the acceleration due to gravity (9.8 m/s^2), and t is the time it takes for the ball to reach the ground (6.0 s).

Plugging in the values:

v = (9.8 m/s^2)(6.0 s)
v = 58.8 m/s

Therefore, the speed of the ball just before hitting the ground is 58.8 m/s.