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Question


The baseball diamond is really a square. The distance between each of the bases is 90 feet.

How far does the catcher have to throw the ball to get from home plate to second base? Round your answer to the nearest foot.
Responses
A 90 feet90 feet
B 100 feet100 feet
C 127 feet127 feet
D 156 feet156 feet
E 180 feet

Answer 1

The distance from home plate to second base on a baseball diamond is the length of two sides of the square plus the length across the diagonal of the square.

Each side is 90 feet, so twice that is 180 feet.

Using the Pythagorean theorem, we can find the length of the diagonal:
diagonal = sqrt(90^2 + 90^2)
diagonal = sqrt(8100 + 8100)
diagonal = sqrt(16200)
diagonal = 127.28 feet

Rounding to the nearest foot, the catcher has to throw the ball approximately 127 feet to get from home plate to second base.

Therefore, the answer is C: 127 feet.