Asked by ⊗WitherRosesNeverDie⊗
Use the image to answer the question.
An illustration shows the unfolded version of a prism with rectangular base. Dimensions are labeled. Three adjoining rectangles are arranged horizontally. The second rectangle has an adjoining triangle on its top and another adjoining triangle on its bottom. The top and bottom of the rectangle form the bases of the triangles. The first rectangle is not labeled. The second rectangle is 5 centimeters long and 3 centimeters wide. The third rectangle is 8 centimeters long. The triangle on top of the second rectangle is labeled 5 centimeters on its base. A side of the top triangle is marked as a line between the top vertex of the triangle which is labeled upper A and the bottom right vertex which is labeled upper B. The bottom triangle is not labeled.
What is the length of AB ?
(1 point)
____cm
An illustration shows the unfolded version of a prism with rectangular base. Dimensions are labeled. Three adjoining rectangles are arranged horizontally. The second rectangle has an adjoining triangle on its top and another adjoining triangle on its bottom. The top and bottom of the rectangle form the bases of the triangles. The first rectangle is not labeled. The second rectangle is 5 centimeters long and 3 centimeters wide. The third rectangle is 8 centimeters long. The triangle on top of the second rectangle is labeled 5 centimeters on its base. A side of the top triangle is marked as a line between the top vertex of the triangle which is labeled upper A and the bottom right vertex which is labeled upper B. The bottom triangle is not labeled.
What is the length of AB ?
(1 point)
____cm
Answers
Answered by
⊗WitherRosesNeverDie⊗
no
Answered by
⊗WitherRosesNeverDie⊗
wrong
Answered by
GPT 3.5
AB is 5 cm.
Answered by
GPT 3.5
Apologies for the mistake in my previous answer.
AB is 3 cm.
AB is 3 cm.
Answered by
GPT 3.5
Apologies for the previous errors.
Given that the second rectangle is 5 cm long and 3 cm wide, and the side connecting points A and B is the diagonal of the rectangle, we can use the Pythagorean theorem to find it.
Using the Pythagorean theorem:
AB^2 = 5^2 + 3^2
AB^2 = 25 + 9
AB^2 = 34
Taking the square root of both sides:
AB = √34 cm
Therefore, the length of line AB is approximately 5.83 cm.
Given that the second rectangle is 5 cm long and 3 cm wide, and the side connecting points A and B is the diagonal of the rectangle, we can use the Pythagorean theorem to find it.
Using the Pythagorean theorem:
AB^2 = 5^2 + 3^2
AB^2 = 25 + 9
AB^2 = 34
Taking the square root of both sides:
AB = √34 cm
Therefore, the length of line AB is approximately 5.83 cm.
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