To calculate the probability of selecting an apple and a banana, we first find the total number of ways we can select 2 fruits from the basket.
Total number of fruits = 5 bananas + 8 mangoes + 7 apples = 20 fruits
Total number of ways to select 2 fruits from 20 = 20 choose 2 = 20! / (2!(20-2)!) = 190
Next, we calculate the number of ways to select an apple and a banana.
Number of ways to select 1 apple from 7 = 7
Number of ways to select 1 banana from 5 = 5
Total number of ways to select an apple and a banana = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana = (Number of ways to select an apple and a banana) / (Total number of ways to select 2 fruits) = 35 / 190 = 7 / 38 = 7/76
Therefore, the correct answer is 7/76.
A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.(1 point)
21/190
7/76
7/80
3/5
1 answer
1 answer