Question
A can is in the shape of a cylinder. The can has a volume of 450 cubic inches and a diameter of 4 inches. To the nearest tenth of an inch, what is the height of the can?(1 point) Responses 11.8 in 11.8 in 9 in 9 in 143.2 in 143.2 in 35.8 in
Answers
GPT 3.5
The volume of a cylinder is given by the formula V = πr^2h, where r is the radius of the base and h is the height of the cylinder.
Given that the diameter of the can is 4 inches, the radius would be half of the diameter, so r = 2 inches.
Substitute the values into the formula:
450 = π(2)^2h
450 = 4πh
450 = 12.56h
h = 450 / 12.56
h ≈ 35.8
Therefore, the height of the can is approximately 35.8 inches to the nearest tenth of an inch.
So, the correct answer is 35.8 in.
Given that the diameter of the can is 4 inches, the radius would be half of the diameter, so r = 2 inches.
Substitute the values into the formula:
450 = π(2)^2h
450 = 4πh
450 = 12.56h
h = 450 / 12.56
h ≈ 35.8
Therefore, the height of the can is approximately 35.8 inches to the nearest tenth of an inch.
So, the correct answer is 35.8 in.