To solve the system of equations:
1. Multiply the first equation by 2 to eliminate the y variable:
-12x + 4y = -64
2. Add the modified first equation to the second equation:
-12x + 4y + 4x + 3y = -64 - 9
-8x + 7y = -73
3. Now, solve the resulting equation for y:
7y = 8x - 73
y = (8x - 73) / 7
4. Substitute the expression for y back into one of the original equations. Let's use the first equation:
-6x + 2((8x - 73) / 7) = -32
5. Solve for x:
-6x + (16x - 146) / 7 = -32
Multiply through by 7 to get rid of the fraction:
-42x + 16x - 146 = -224
-26x = -78
x = 3
6. Now that we have found x, we can substitute it back in to find y:
y = (8(3) - 73) / 7
y = (24 - 73) / 7
y = -49 / 7
y = -7
Therefore, the solution to the system of equations is x = 3 and y = -7.
Solve the system of equations.
-6x + 2y = -32
4x + 3y = -9 (1 point)
1 answer
2 answers