To solve this system of equations, we can use the method of substitution. First, we can rearrange the equations to make one variable the subject:
From the first equation:
2y = 6x - 32
y = 3x - 16
Now, we can substitute this expression for y into the second equation:
4x + 3(3x - 16) = -9
4x + 9x - 48 = -9
13x - 48 = -9
13x = 39
x = 3
Now that we have found the value of x, we can substitute it back into the equation y = 3x - 16 to find the value of y:
y = 3(3) - 16
y = 9 - 16
y = -7
Therefore, the solution to the system of equations is x = 3 and y = -7.
Solve the system of equations.
-6x + 2y = -32
4x + 3y = -9 (1 point)
1 answer