put this differently\represent the surface area of a square pyramid with base length \(b\) and slant height \(s\) as:

Question

\[A = b^2 + 2bs\]

Given that the base length is 12 and the slant height is 18, we can substitute these values into the formula:

\[A = 12^2 + 2(12)(18)\]

\[A = 144 + 432\]

\[A = 576\]

Therefore, the surface area of the square pyramid is 576 square units.

Answer 1

The surface area of a square pyramid is calculated by adding the square of the base length to twice the base length multiplied by the slant height.

Substituting the given values of base length (12) and slant height (18) into the formula, we get:

Surface Area = \(12^2 + 2(12)(18)\)
= \(144 + 432\)
= 576 square units

Therefore, the surface area of the square pyramid is 576 square units.