What is the solution set for 2x^2 + x - 15 = 0?

3 answers

The solution set for the quadratic equation 2x^2 + x - 15 = 0 can be found by factoring or using the quadratic formula.

To factor the equation, we need to find two numbers that multiply to -30 (the product of the coefficient of x^2 and the constant term) and add up to 1 (the coefficient of x). These numbers are 6 and -5.

Therefore, we can rewrite the equation as:

(2x + 6)(x - 5) = 0

Setting each factor to zero, we get:

2x + 6 = 0 or x - 5 = 0

Solving for x, we get:

2x = -6 or x = 5

x = -3 or x = 5

So, the solution set for the equation 2x^2 + x - 15 = 0 is x = -3 or x = 5.
is it
{2.5,-3}
{3,-2.5}
{15,1.5}
{-15,-1.5}
The correct solution set for the equation 2x^2 + x – 15 = 0 is:

x = 2.5 and x = -3

Therefore, the correct solution set is {2.5, -3}.