To solve this system of equations by substitution, we can solve one of the equations for one variable and then substitute that expression into the other equation.
Given equations:
1) 3x - y = 6
2) -4x + 2y = -8
First, we can solve equation 1 for y:
3x - y = 6
y = 3x - 6
Next, we substitute this expression for y into equation 2:
-4x + 2(3x - 6) = -8
-4x + 6x - 12 = -8
2x - 12 = -8
2x = -8 + 12
2x = 4
x = 4/2
x = 2
Now, we substitute the value of x back into the equation we solved for y:
y = 3(2) - 6
y = 6 - 6
y = 0
Therefore, the solution to the system of equations is x = 2 and y = 0.
3x-y=6 and -4x+2y=-8 substation
1 answer
1 answer