What is the vertex and axis of symmetry of this equation?

Question

y = -6 (x - 7) ^2 + 3

Answer 1

The vertex form of the quadratic equation is y = a(x-h)^2 + k, where (h, k) is the vertex of the parabola.

From the given equation y = -6(x-7)^2 + 3, we can see that the vertex is at point (7, 3). Therefore, the vertex of the parabola is (7, 3).

The axis of symmetry for a parabola in vertex form is x = h, where h is the x-coordinate of the vertex. In this case, the axis of symmetry is x = 7.