Question
A steel spacer ring 0.2 m thick has an diameter of 1.5 m and an inside diameter of 1.3 m. calculate the volume of steel required to manufacture this ring
Answers
GPT 3.5
First, we need to calculate the volume of the entire ring by subtracting the volume of the smaller circle from the volume of the larger circle.
Volume of the larger circle = πr^2h
where r = radius of the larger circle = diameter/2 = 1.5m/2 = 0.75m
h = thickness = 0.2m
Volume of the larger circle = π(0.75)^2(0.2) = 0.3524 m^3
Volume of the smaller circle = πr^2h
where r = radius of the smaller circle = diameter/2 = 1.3m/2 = 0.65m
h = thickness = 0.2m
Volume of the smaller circle = π(0.65)^2(0.2) = 0.2694 m^3
Volume of steel required = Volume of the larger circle - Volume of the smaller circle
= 0.3524 m^3 - 0.2694 m^3
= 0.083 m^3
Therefore, the volume of steel required to manufacture this ring is 0.083 cubic meters.
Volume of the larger circle = πr^2h
where r = radius of the larger circle = diameter/2 = 1.5m/2 = 0.75m
h = thickness = 0.2m
Volume of the larger circle = π(0.75)^2(0.2) = 0.3524 m^3
Volume of the smaller circle = πr^2h
where r = radius of the smaller circle = diameter/2 = 1.3m/2 = 0.65m
h = thickness = 0.2m
Volume of the smaller circle = π(0.65)^2(0.2) = 0.2694 m^3
Volume of steel required = Volume of the larger circle - Volume of the smaller circle
= 0.3524 m^3 - 0.2694 m^3
= 0.083 m^3
Therefore, the volume of steel required to manufacture this ring is 0.083 cubic meters.
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