Yep you are right, we are helping each other out... actually we have the problems in a multiple choice format, but we cant get the answers, if u may help us... here is the list of problems with the choices,...
tnx
Question2
In (dy/dx) + yP(x) = y^n Q(x), if n = 1 the equation would be reduced to a
A Bernoulli Equation
B Exact equation
C Variable Separable
question 3
Question3 Transform 2xdy - y(x+1)dx + 6y^3dx = 0 into a Bernoulli Equation.
A (dy/dx) - y(1+ 1/x) = 3y^3(1/x)
B y ' - [y(x + 1)/2x] = 3y^3/x
C (dy/dx) - (x + 1)/xy^2 = (3/2x)
question 4
Question4 The slope of the normal line to y^2 = x/2 at P(1/8,1/4) is ____.
A 1/16
B -1/8
C -1/4
question 5
Question5 The orthogonal trajectory of y^2 - x^2 = C is___.
A ln y/x = C
B xy = c
C lny = lnx + C
question 6
Question6 The given functions cos x, sin x, and
cos (x-pi/6) are said to be _____.
A linearly dependent
B linearly independent
C a relation
question 7
Question7 If the Wronskian of the given functions is not equal to 0, then the functions are said to be____.
A linearly dependent
B linearly independent
C inconsistent
question 8
Question8 The functional determinant of x, e^x, and e^-x is equal to___.
A 0
B 2
C 2x
question 9
Question9 The equation of the tangent line of the one-family of curve x^2 + y^2 = 25 at
P(4, 3) is _______.
A 4x -3y + 25 = 0
B 4x + 3y - 25 = 0
C 3x + 4y -24 = 0
Question10 The complete solution of 2x^3 dy = y (y^2 + 3x^2) is _____.
A y^2 = (c - x) x^3
B y^2 (c - x ) = x^3
C x^2 (c -x) = y^3
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help...
3 answers
However, if the questions come from the same person, it would be advantageous to post using the same name, because teachers will have the latitude of referring to previously solved problems, and the student will benefit from the continuity.
Many of the questions have been answered. So it is a matter of time that the remaining questions will be responded.
It is also important to note that what we offer here is help, not answers. The students have to put in their shares to benefit from the learning process. In general, that means that students have to post their work and identify where help is needed.
In (dy/dx) + yP(x) = y^n Q(x), if n = 1 the equation would be reduced to a
A Bernoulli Equation
B Exact equation
C Variable Separable
When n=1, the equation reduces to:
y' + yP(x) = yQ(x)
y' = y(P(x)+Q(x))
y'/y = P(x) + Q(x)
Does that look familiar to you?
http://en.wikipedia.org/wiki/Wronskian