Use implicit differentiation to get
2x+2yy'=0
from which
y'=-x/y=-4/3
The tangent line is therefore
(y-3)=(-4/3)(x-4)
Simplify if necessary.
What is the equation of the tangent line of the one-family of curve x^2 + y^2 = 25 at
P(4, 3) ??
help please
3 answers
I have 3 choices for that
A 4x -3y + 25 = 0
B 4x + 3y - 25 = 0
C 3x + 4y -24 = 0
i dunno what is the correct answer
A 4x -3y + 25 = 0
B 4x + 3y - 25 = 0
C 3x + 4y -24 = 0
i dunno what is the correct answer
Expand (y-3)=(-4/3)(x-4)
and move all the terms to the left hand side, and you should find that the equation matches one of the answers.
If it does not, post what you've got.
and move all the terms to the left hand side, and you should find that the equation matches one of the answers.
If it does not, post what you've got.