Find the vertex of y=3x2−12x+2 (1 point)Responses(-2,-10) (-2,-10)(6,-106) (6,-106)(2,-10)(2,-10)(6,-34)

Answer 1

The vertex of the given quadratic function y=3x^2-12x+2 can be found using the formula x=-b/(2a), where a=3 and b=-12 in this case.

x = -(-12)/(2*3)
x = 12/6
x = 2

To find the y-coordinate of the vertex, substitute x=2 back into the equation:
y = 3*(2)^2 - 12*(2) + 2
y = 3*4 - 24 + 2
y = 12 - 24 + 2
y = -10

Therefore, the vertex of the quadratic function y=3x^2-12x+2 is (2, -10).