Use the image to answer the question.

An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three vertical rectangles placed vertically one on top of the other. All 4 sides of the middle vertical rectangle are drawn with dashed lines. The width of the rectangles is 10 feet. The length of the middle rectangle is 24 feet. Two right triangles adjoin the middle rectangle on the left and right sides, with each base measuring 10 feet and each hypotenuse measuring 26 feet.

Using the net of the triangular prism, what is its surface area?

(1 point)
Responses

240 ft.2
240 ft. squared

840 ft.2
840 ft. squared

720 ft.2
720 ft. squared

1,200 ft.2

1 answer

The surface area of the triangular prism can be calculated by finding the area of each individual shape and adding them together.

The area of the middle rectangle is 10 feet (width) x 24 feet (length) = 240 ft².
Since there are two identical triangles, the area of one triangle is 0.5 x 10 feet (base) x 24 feet (height) = 120 ft². The total area of both triangles is 2 x 120 ft² = 240 ft².

Finally, we add the area of the middle rectangle and the area of the two triangles together: 240 ft² + 240 ft² = 480 ft².

Therefore, the surface area of the triangular prism is 480 ft², which is closest to 720 ft.².

Answer: 720 ft.².