Let's set up an equation to solve for the time it takes for the two aquariums to contain the same amount of water:
For Aquarium I:
Initial amount of water in Aquarium I = 4.6 gallons
Rate at which water is being added to Aquarium I = 1.2 gallons/minute
Amount of water in Aquarium I after t minutes = 4.6 + 1.2t
For Aquarium II:
Initial amount of water in Aquarium II = 54.6 gallons
Rate at which water is being drained from Aquarium II = 0.8 gallons/minute
Amount of water in Aquarium II after t minutes = 54.6 - 0.8t
Setting the two equations equal to each other:
4.6 + 1.2t = 54.6 - 0.8t
1.2t + 0.8t = 54.6 - 4.6
2t = 50
t = 25
Therefore, it will take 25 minutes for both aquariums to contain the same amount of water. So, the correct answer is 25 minutes.
Aquarium I contains 4.6 gallons of water. Louise will begin filling Aquarium I at a rate of 1.2 gallons per minute.
Aquarium II contains 54.6 gallons of water. Isaac will begin draining Aquarium II at a rate of 0.8 gallon per minute.
After how many minutes will both aquariums contain the same amount of water.
(pick an answer)
25 minutes
125 minutes
50 minutes
148 minutes
1 answer