Question

differentiate (solve)
y=sin(2x+1)

Answer 1

To differentiate the given function, we need to apply the chain rule.

Let u = 2x + 1.

Then, y = sin(u).

Now, differentiate with respect to x:

dy/dx = dy/du * du/dx
dy/du = cos(u)
du/dx = 2

Substitute u back in:

dy/dx = cos(2x + 1) * 2
dy/dx = 2cos(2x + 1)

Therefore, the derivative of y = sin(2x + 1) is dy/dx = 2cos(2x + 1).