Asked by Ana

70 J of work are done on the gas in the process shown in the figure.
What is V_f in cm^3 ?
I have a graph but I can't post it here.

My values are
W=70J
P=200kPa which is 200000Pa

I used the formula W=P(deltaV)
then to get deltaV you do: deltaV= W(P)
so i did 70J/200000pa= 2vf so i get 1.75e-4
is is right?
Answered by Ana
is it right?
Answered by drwls
It is true that Work = P*(delta V) (if P is constant during the process). How to you get from there to
delta V= W(P) ?

It seems to me that delta V = W/P

I can't be of much further help without seeing the figure. Sorry.
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