70 J of work are done on the gas in the process shown in the figure.
What is V_f in cm^3 ?
I have a graph but I can't post it here.
My values are
W=70J
P=200kPa which is 200000Pa
I used the formula W=P(deltaV)
then to get deltaV you do: deltaV= W(P)
so i did 70J/200000pa= 2vf so i get 1.75e-4
is is right?
2 answers
is it right?
It is true that Work = P*(delta V) (if P is constant during the process). How to you get from there to
delta V= W(P) ?
It seems to me that delta V = W/P
I can't be of much further help without seeing the figure. Sorry.
delta V= W(P) ?
It seems to me that delta V = W/P
I can't be of much further help without seeing the figure. Sorry.
0 answers