Question

A toy car runed off the edge of a table that is 1.225m high. If the car lands 0.400m from the base of the car to fall,
a)how long does it take the car to fall
2(1.225)/-9.80=-0.25=0.5s
b)what is the horizontal velocity of the car?

Answer 1

Actually, the time to fall is
T = sqrt (2H/g).

That seems to be what you did, but you were incorrect in writing
-0.25 = .50
Also since you are measuring distance down, forget the minus sign.

Once you get the time T, use
T = D/Vx to get the horizontal velocity, Vx.

Answer 2

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