There are three choices of fruit are bananas, pears, and oranges. If the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, what is the probability of getting an orange?

Question

Responses

Answer 1

Let the probability of getting an orange be x.

Given:
Probability of getting a banana = 5/12
Probability of getting a pear = 1/6
Probability of getting an orange = x

Since the total probability of all three choices must add up to 1, we have:
5/12 + 1/6 + x = 1

Solving for x:
5/12 + 1/6 + x = 1
10/12 + 2/12 + x = 1
12/12 + x = 1
x = 1 - 1
x = 0

Therefore, the probability of getting an orange is 0.