Paul is at a game show and wins if he can toss a coin and get heads and spin a C on a spinner that has three equal sections. What is the probability that Paul will win?

Answer 1

Since there are 2 equally likely outcomes when tossing a coin (heads or tails) and 3 equally likely outcomes when spinning the spinner (C, A, or B), the total number of possible outcomes is 2 * 3 = 6.

For Paul to win, he needs to get heads on the coin toss and spin a C on the spinner. There is only 1 way for both of these events to occur, so the number of favorable outcomes is 1.

Therefore, the probability that Paul will win is the number of favorable outcomes divided by the total number of possible outcomes, which is:

1/6 = 0.1667 or 16.67%