To solve this system of equations using substitution, we will first solve one of the equations for one variable and then substitute that expression into the other equation.
Given equations:
1) 6x - 5y = 27
2) 3x + 5y = 36
From equation 2, we can solve for y:
3x + 5y = 36
5y = 36 - 3x
y = (36 - 3x) / 5
Now we substitute this expression for y into equation 1:
6x - 5((36 - 3x) / 5) = 27
6x - 36 + 3x = 27
9x - 36 = 27
9x = 63
x = 7
Now that we have found the value of x, we can substitute it back into the expression we found for y:
y = (36 - 3(7)) / 5
y = (36 - 21) / 5
y = 15 / 5
y = 3
Therefore, the solution to the system of equations is x = 7 and y = 3.
Solve the system of two equations using substitution.
6x-5y=27
3x+5y=36
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