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The slope of line j is -5/7. Since line k is parallel to line j, it will have the same slope.
Using the point-slope form of a linear equation, we have:
y - y₁ = m(x - x₁)
y - 5 = -5/7(x + 9)
Expanding and rearranging, we get:
y = -5/7x - 45/7 + 5
y = -5/7x - 20/7
Therefore, the equation of line k in slope-intercept form is y = -5/7x - 20/7.