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solve the equation and please show the work.
sqrt x+2-5=0
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solve each equation. check for extraneous solutions.
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solve each equation. check for extraneous solution.
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Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.
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When I solve the inquality 2x^2 - 6 < 0,
I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or
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