A force 3N stretches an elastic material y 30mm. What additional force will stretch the material 35mm? assume that the elastic limit is nor exceeded

Answer 1

To find the additional force needed to stretch the material an additional 5mm, we can use a proportionality equation:

F1/y1 = F2/y2

Where F1 is the initial force (3N), y1 is the initial stretch (30mm), F2 is the additional force we want to find, and y2 is the additional stretch (35mm).

Plugging in the values:

3N / 30mm = F2 / 35mm

Solving for F2:

F2 = 3N * (35mm / 30mm)
F2 = 3N * 1.167

F2 ≈ 3.5N

Therefore, an additional force of approximately 3.5N will stretch the material an additional 5mm.