To solve the system of equations, we can use the method of substitution.
From the second equation, we have x = 6y + 22.
Now, we can substitute x = 6y + 22 into the first equation:
5(6y + 22) + 2y = 14
30y + 110 + 2y = 14
32y + 110 = 14
32y = -96
y = -3
Now, we can substitute y = -3 back into x = 6y + 22:
x = 6(-3) + 22
x = -18 + 22
x = 4
Therefore, the solution to the system of equations is x = 4 and y = -3.
Solve the system of equations.
5x+2y=14
x−6y=22(1 point)
1 answer