I'm trying to find the cosecant of 11 pi/6. The answer is -2, but I'm not sure where this came from. I thought You would flip the sine value which was sq. root of 3/2, making it 2/sq. root of three, which would then become sq. root of -6 over 3 or sq. root of -2. Why isn't there a sq. root sign? Thanks!!!

2 answers

11pi/6 is just pi/6 short of 2pi
so csc 11pi/6
= csc (-pi/6)
= -csc pi/6
= -1/sin pi/6
= -1/(1/2), [sin 30ยบ = sin pi/6 = 1/2]
= -2
I don't understand the math please

I don't understand the math please .
I don't understand the math please.