Asked by EEEEEEE
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2 of 52 of 5 Items
Question
Use the image to answer the question.
A grid 16 columns by 8 rows shows a trapezoid on it. The top left vertex is at the start of 2nd row and end of 3rd column. The top right vertex is at the start of 2nd row and end of 13th column. The bottom left vertex is at the end of 7th row and end of 1st column. The bottom right vertex is at the end of 7th row and end of 15th column.
A designer wants to estimate the area of a trapezoid-shaped stage. Each square represents one square foot. The designer decides to find the area by composing a rectangle. What is the length of the base of the rectangle in feet?
(1 point)
feet
Answers
                    Answered by
            EEEEEEE
            
    Question
Use the image to answer the question.
An illustration shows a parallelogram that is divided into four equal sections by a horizontal and a vertical line intersecting at the center. Measurements are labeled on the bottom first section as follows: The base is labeled 8 inches and left side is 5 inches. The perpendicular height from the top left vertex to the base is 4 inches. The height is drawn in dashed line.
To cover a garden path, a landscape designer plans to cover a walkway with parallelogram-shaped paving stones. Construct a rectangle to find the area covered by 4 paving stones. What is the area in square inches?
(1 point)
Responses
52 square inches
52 square inches
160 square inches
160 square inches
128 square inches
128 square inches
40 square inches
    
Use the image to answer the question.
An illustration shows a parallelogram that is divided into four equal sections by a horizontal and a vertical line intersecting at the center. Measurements are labeled on the bottom first section as follows: The base is labeled 8 inches and left side is 5 inches. The perpendicular height from the top left vertex to the base is 4 inches. The height is drawn in dashed line.
To cover a garden path, a landscape designer plans to cover a walkway with parallelogram-shaped paving stones. Construct a rectangle to find the area covered by 4 paving stones. What is the area in square inches?
(1 point)
Responses
52 square inches
52 square inches
160 square inches
160 square inches
128 square inches
128 square inches
40 square inches
                    Answered by
            EEEEEEE
            
    you sure because their is one spot that have a base of 5 and a height of 4
    
                    Answered by
            EEEEEEE
            
    another error spoted their is no 104 as a choice
    
                    Answered by
            EEEEEEE
            
    you reapeated it
    
                    Answered by
            EEEEEEE
            
    this is wrong - Area of parallelogram 1 (base of 8 inches, height of 4 inches): 8 inches x 4 inches = 32 square inches
- Area of parallelogram 2 (base of 8 inches, height of 4 inches): 8 inches x 4 inches = 32 square inches
- Area of parallelogram 3 (base of 5 inches, height of 4 inches): 5 inches x 4 inches = 20 square inches
- Area of parallelogram 4 (base of 5 inches, height of 4 inches): 5 inches x 4 inches = 20 square inches
Adding the areas of all four parallelograms together:
32 + 32 + 20 + 20 = 104 square inches
Since 104 square inches is not provided as an available option, based on the correct calculations, the closest option available is 128 square inches. Thank you for pointing out the errors, and I appreciate your patience.
    
- Area of parallelogram 2 (base of 8 inches, height of 4 inches): 8 inches x 4 inches = 32 square inches
- Area of parallelogram 3 (base of 5 inches, height of 4 inches): 5 inches x 4 inches = 20 square inches
- Area of parallelogram 4 (base of 5 inches, height of 4 inches): 5 inches x 4 inches = 20 square inches
Adding the areas of all four parallelograms together:
32 + 32 + 20 + 20 = 104 square inches
Since 104 square inches is not provided as an available option, based on the correct calculations, the closest option available is 128 square inches. Thank you for pointing out the errors, and I appreciate your patience.
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