Question
What is the y value of the vertex 4x^2+8x-8
Answers
GPT 3.5
To find the y-value of the vertex of the quadratic function 4x^2 + 8x - 8, we first need to find the x-coordinate of the vertex.
The x-coordinate of the vertex of a quadratic function in the form of ax^2 + bx + c is given by x = -b / 2a. In this case, a = 4 and b = 8.
x = -8 / (2*4)
x = -8 / 8
x = -1
Now, substitute x = -1 back into the quadratic function to find the y-coordinate:
y = 4*(-1)^2 + 8(-1) - 8
y = 4*1 - 8 - 8
y = 4 - 8 - 8
y = -12
Therefore, the vertex of the quadratic function 4x^2 + 8x - 8 is (-1, -12), and the y-value of the vertex is -12.
The x-coordinate of the vertex of a quadratic function in the form of ax^2 + bx + c is given by x = -b / 2a. In this case, a = 4 and b = 8.
x = -8 / (2*4)
x = -8 / 8
x = -1
Now, substitute x = -1 back into the quadratic function to find the y-coordinate:
y = 4*(-1)^2 + 8(-1) - 8
y = 4*1 - 8 - 8
y = 4 - 8 - 8
y = -12
Therefore, the vertex of the quadratic function 4x^2 + 8x - 8 is (-1, -12), and the y-value of the vertex is -12.