To calculate the amount of CO2 produced from the decomposition of 200 g of CaCO3 when 112 g of CaO are produced, we need to first determine the molar masses of CaCO3 and CaO.
The molar mass of CaCO3 (calcium carbonate) is:
Ca: 40.08 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
Therefore, the molar mass of CaCO3 is:
40.08 g/mol + 12.01 g/mol + (3 * 16.00 g/mol) = 100.09 g/mol
The molar mass of CaO (calcium oxide) is:
Ca: 40.08 g/mol
O: 16.00 g/mol
Therefore, the molar mass of CaO is:
40.08 g/mol + 16.00 g/mol = 56.08 g/mol
Next, we need to calculate the moles of CaCO3 in 200 g:
moles of CaCO3 = mass / molar mass
moles of CaCO3 = 200 g / 100.09 g/mol = 1.999 moles
From the balanced chemical equation for the decomposition of CaCO3:
CaCO3 -> CaO + CO2
We can see that 1 mole of CaCO3 yields 1 mole of CaO and 1 mole of CO2. Therefore, 1.999 moles of CaCO3 will yield 1.999 moles of CaO and 1.999 moles of CO2.
Finally, we can calculate the mass of CO2 produced from the moles:
mass of CO2 = moles of CO2 x molar mass of CO2
mass of CO2 = 1.999 moles x 44.01 g/mol = 87.97 g
Therefore, from the decomposition of 200 g of CaCO3, if 112 g of CaO are produced, 87.97 g of CO2 are also produced.
How much CO2 is produced from the decomposition of 200 g of CaCO3 if 112g or CaO are produced?
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1 answer