To solve the system of equations, we can use the method of substitution or elimination.
Using the elimination method, we can multiply the first equation by 2 and the second equation by 3 to make the coefficients of y equal and then add the two equations together to eliminate y.
-12x + 4y = -64
12x + 9y = -27
When we add the two equations together, we get:
13y = -91
y = -91 / 13
y = -7
Now that we have the value of y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:
-6x + 2(-7) = -32
-6x - 14 = -32
-6x = -18
x = 3
Therefore, the solution to the system of equations is x = 3 and y = -7.
Question Solve the system of equations. −6x+2y=−32 4x+3y=−9 (1 point)
1 answer