Water is added to two containers for 16 minutes. The equations below model the ounces of water, y, in each container after x minutes. At the time after the start when the containers hold the same amount of water, how much water do they hold?

Question

Container A: y=16x+104
Container b: y=-2x^2+40x+160
16 minutes

Answer 1

To find the amount of water each container holds after 16 minutes, we can substitute x=16 into the equations:

For container A:
y = 16(16) + 104
y = 256 + 104
y = 360

For container B:
y = -2(16)^2 + 40(16) + 160
y = -2(256) + 640 + 160
y = -512 + 640 + 160
y = 288

So, after 16 minutes, container A holds 360 ounces of water and container B holds 288 ounces of water.