Question

Calculate [H3O^+] for a solution of nitric acid for which pH = 5.73. Be sure your answer has the correct number of significant figures.

Answer 1

Given that pH = 5.73, we can use the equation:

pH = -log[H3O^+]

5.73 = -log[H3O^+]

-5.73 = log[H3O^+]

[H3O^+] = 10^(-5.73)

[H3O^+] = 1.94 x 10^(-6) M

Therefore, [H3O^+] for a solution of nitric acid with a pH of 5.73 is 1.94 x 10^(-6) M.