If the graphs of f(x) = 2x + 3 and g(x) = 3(b)^2 intersect only once, which is a possible value of b? A1.7 B.17 C.2 D.1/2

Answer 1

C. 2

If the graphs intersect only once, it means that the equations are not equal to each other. Therefore, setting f(x) = g(x) gives:

2x + 3 = 3b^2

Solving for b:

2x + 3 = 3b^2

2(0) + 3 = 3b^2

3 = 3b^2

1 = b^2

b = 1 or b = -1

Since b must be positive, the possible value is b = 2.