Kyle wishes to fly to a point 450 km due south in 3 hours. A wind is blowing from the west at 50 km/hr. Compute the proper heading and speed that Kyle must choose in order to reach his destination on time.

Answer 1

His southerly velocity must be 450km/3hrs.

Now draw the vectors. You have a resultant, Due South, of 150km/hr, a component due E at 50km/hr, Let theta be the angle of his flying, so on my diagram, I see tan Theta= 150/50=3
or Theta= 71.6deg S of W, or a heading of
270-71.6=198.4 deg
check that.
His speed? 50/speed=cos71.4, solve for speed
Double check me on all this.