Asked by winter<3
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A coordinate plane shows the x-axis, labeled as hours, ranging from 0 to 6 in increments of 1 and the y-axis, labeled as gallons, ranging from 0 to 240 in increments of 20. A line segment joins four plotted points. The coordinates of the plotted points are left parenthesis 0 comma 200 right parenthesis, left parenthesis 1 comma 160 right parenthesis, left parenthesis 3 comma 80 right parenthesis, and left parenthesis 5 comma 0 right parenthesis.
The graph shows the number of gallons in a wading pool that is being drained. Using the points (1,160) and (3,80) as (x1,y1) and (x2,y2) , what is the rate of change in the number of gallons in the pool after each hour has passed?
(1 point)
Responses
−40 gal./hr.
negative 40 gal./hr.
40 gal./hr.
40 gal./hr.
−140 gal./hr.
negative Start Fraction 1 over 40 End Fraction gal./hr.
140 gal./hr.
Start Fraction 1 over 40 End Fraction gal./hr.
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A coordinate plane shows the x-axis, labeled as hours, ranging from 0 to 6 in increments of 1 and the y-axis, labeled as gallons, ranging from 0 to 240 in increments of 20. A line segment joins four plotted points. The coordinates of the plotted points are left parenthesis 0 comma 200 right parenthesis, left parenthesis 1 comma 160 right parenthesis, left parenthesis 3 comma 80 right parenthesis, and left parenthesis 5 comma 0 right parenthesis.
The graph shows the number of gallons in a wading pool that is being drained. Using the points (1,160) and (3,80) as (x1,y1) and (x2,y2) , what is the rate of change in the number of gallons in the pool after each hour has passed?
(1 point)
Responses
−40 gal./hr.
negative 40 gal./hr.
40 gal./hr.
40 gal./hr.
−140 gal./hr.
negative Start Fraction 1 over 40 End Fraction gal./hr.
140 gal./hr.
Start Fraction 1 over 40 End Fraction gal./hr.
Skip to navigation
Answers
There are no human answers yet.
Answered by
GPT 3.5
The rate of change in the number of gallons in the pool after each hour has passed can be calculated using the formula:
Rate of change = (y2 - y1) / (x2 - x1)
Substitute the values:
Rate of change = (80 - 160) / (3 - 1)
Rate of change = (-80) / 2
Rate of change = -40 gallons per hour
Therefore, the rate of change in the number of gallons in the pool after each hour has passed is -40 gallons per hour. This can also be written as negative 40 gallons per hour.
Rate of change = (y2 - y1) / (x2 - x1)
Substitute the values:
Rate of change = (80 - 160) / (3 - 1)
Rate of change = (-80) / 2
Rate of change = -40 gallons per hour
Therefore, the rate of change in the number of gallons in the pool after each hour has passed is -40 gallons per hour. This can also be written as negative 40 gallons per hour.
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