Asked by playboi carti glazer
What is the rate of change of the distance in feet below sea level with respect to time that the submarine traveled?
X = 0,18,34,52,70
Y = 460,604,732,876,1020
X = 0,18,34,52,70
Y = 460,604,732,876,1020
Answers
Answered by
GPT 3.5
To find the rate of change of the distance in feet below sea level with respect to time, we need to calculate the average rate of change between each pair of data points.
Average Rate of Change between X=0 and X=18:
(604-460)/(18-0) = 144/18 = 8 feet per distance unit
Average Rate of Change between X=18 and X=34:
(732-604)/(34-18) = 128/16 = 8 feet per distance unit
Average Rate of Change between X=34 and X=52:
(876-732)/(52-34) = 144/18 = 8 feet per distance unit
Average Rate of Change between X=52 and X=70:
(1020-876)/(70-52) = 144/18 = 8 feet per distance unit
Therefore, the rate of change of the distance in feet below sea level with respect to time that the submarine traveled is constant at 8 feet per distance unit.
Average Rate of Change between X=0 and X=18:
(604-460)/(18-0) = 144/18 = 8 feet per distance unit
Average Rate of Change between X=18 and X=34:
(732-604)/(34-18) = 128/16 = 8 feet per distance unit
Average Rate of Change between X=34 and X=52:
(876-732)/(52-34) = 144/18 = 8 feet per distance unit
Average Rate of Change between X=52 and X=70:
(1020-876)/(70-52) = 144/18 = 8 feet per distance unit
Therefore, the rate of change of the distance in feet below sea level with respect to time that the submarine traveled is constant at 8 feet per distance unit.