the grand canyon is 1600 meters deep at its deeoest point. a rock is dropped fromthe rim above this point. Express the height of the rock as a function T in seconds. how long will it take the rock to hit the canyon floor?

Question

H= 1600-1/2t^2
thats what i got as a function is that correct cause it doesnt work to get the final answer on how long it would take the rock to hit the floor.

Answer 1

You forgot the acceleration of gravity before the t^2

H = Ho - (1/2)gt^2 = 1600 -(9.8/2)t^2
Set that equal to 0 and solve for t.