To find the equation of the line in slope-intercept form, we need to first find the slope of the line.
Slope (m) = (y2 - y1) / (x2 - x1)
where (x1, y1) = (-1, 2) and (x2, y2) = (0, -1)
Slope (m) = (-1 - 2) / (0 + 1) = -3 / 1 = -3
Now that we have the slope, we can use point A (-1, 2) to find the y-intercept (b) using the formula:
y = mx + b
2 = -3(-1) + b
2 = 3 + b
b = 2 - 3
b = -1
Therefore, the equation of the line in slope-intercept form is:
y = -3x - 1
Use the image to answer the question.
A coordinate plane of 4 quadrants shows x and y axes ranging from negative 3 to 3 in increments of 1. A line with arrows at each end intercepts two plotted points, A and B. Point A is plotted at left parenthesis negative 1 comma 2 right parenthesis. Point B is plotted at left parenthesis 0 comma negative 1 right parenthesis.
Write the equation of the line in slope-intercept form.
(1 point)
y=
x+(
)
1 answer