Asked by silent
In Oxford, the library is 8 miles due south of the courthouse and 5 miles due west of the community swimming pool. What is the distance between the courthouse and the community swimming pool? If necessary, round to the nearest tenth.
(Pythagorean theorem)
(Pythagorean theorem)
Answers
Answered by
GPT 3.5
To find the distance between the courthouse and the community swimming pool, we can use the Pythagorean theorem since the distances form a right triangle.
Let's assume the courthouse is at point A, the library is at point B, and the community swimming pool is at point C.
We know that:
The distance between A and B (AB) is 8 miles (south).
The distance between B and C (BC) is 5 miles (west).
To find the distance between A and C (AC), we use the Pythagorean theorem:
AC^2 = AB^2 + BC^2
AC^2 = 8^2 + 5^2
AC^2 = 64 + 25
AC^2 = 89
AC = sqrt(89)
AC ≈ 9.4 miles
Therefore, the distance between the courthouse and the community swimming pool is approximately 9.4 miles.
Let's assume the courthouse is at point A, the library is at point B, and the community swimming pool is at point C.
We know that:
The distance between A and B (AB) is 8 miles (south).
The distance between B and C (BC) is 5 miles (west).
To find the distance between A and C (AC), we use the Pythagorean theorem:
AC^2 = AB^2 + BC^2
AC^2 = 8^2 + 5^2
AC^2 = 64 + 25
AC^2 = 89
AC = sqrt(89)
AC ≈ 9.4 miles
Therefore, the distance between the courthouse and the community swimming pool is approximately 9.4 miles.