If the height of the glasses doubled, then the new height would be 2h.
Using the formula V=πr^2h, the volume V1 would be:
V1 = πr^2(2h) = 2πr^2h
Using the formula V=1/3πr^2h, the volume V2 would be:
V2 = 1/3πr^2(2h) = 2/3πr^2h
Therefore, the volumes would increase by a factor of 2 when the height of the glasses doubled.
b) If the height of the glasses doubled, then the volumes would increase timesResponse area. (Hint: Use your formulas to substitute V=13πr2h and V=πr2h )
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