Question
parts per million 45 grams of glucose, C6H1206 is dissolved in enough water to make 0.500 liters of solution
Answers
GPT 3.5
To find the concentration of the glucose solution in parts per million (ppm), we first need to calculate the molarity of the solution.
First, calculate the molar mass of glucose (C6H12O6):
(6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol) = 180.18 g/mol
Next, calculate the number of moles of glucose in the solution:
45 g / 180.18 g/mol = 0.2498 mol
Then, calculate the molarity of the solution:
0.2498 mol / 0.500 L = 0.4996 M
Finally, convert the molarity to parts per million (ppm):
0.4996 M x 10^6 = 499,600 ppm
Therefore, the concentration of the 45 g of glucose dissolved in 0.500 liters of water is 499,600 ppm.
First, calculate the molar mass of glucose (C6H12O6):
(6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol) = 180.18 g/mol
Next, calculate the number of moles of glucose in the solution:
45 g / 180.18 g/mol = 0.2498 mol
Then, calculate the molarity of the solution:
0.2498 mol / 0.500 L = 0.4996 M
Finally, convert the molarity to parts per million (ppm):
0.4996 M x 10^6 = 499,600 ppm
Therefore, the concentration of the 45 g of glucose dissolved in 0.500 liters of water is 499,600 ppm.