parts per million 45 grams of glucose, C6H1206 is dissolved in enough water to make 0.500 liters of solution

Answer 1

To find the concentration of the glucose solution in parts per million (ppm), we first need to calculate the molarity of the solution.

First, calculate the molar mass of glucose (C6H12O6):
(6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol) = 180.18 g/mol

Next, calculate the number of moles of glucose in the solution:
45 g / 180.18 g/mol = 0.2498 mol

Then, calculate the molarity of the solution:
0.2498 mol / 0.500 L = 0.4996 M

Finally, convert the molarity to parts per million (ppm):
0.4996 M x 10^6 = 499,600 ppm

Therefore, the concentration of the 45 g of glucose dissolved in 0.500 liters of water is 499,600 ppm.