Question

Solve the system of two equations.
3x - 4y = 40
5x - 5y = 55

A) (14,3)
B) (8,-3)
C) (4,-7)
D) (18,7)

Answer 1

To solve this system of equations, we can use either the substitution method or the elimination method. Let's use the elimination method:

First, we multiply the second equation by 4 to line up the coefficients of y in both equations:
3x - 4y = 40
20x - 20y = 220

Now, we can subtract the first equation from the modified second equation to eliminate y:
17x = 180
x = 180/17
x = 10.59 (approximately)

Now, we can substitute x back into the first equation to solve for y:
3(10.59) - 4y = 40
31.77 - 4y = 40
-4y = 8.23
y = -8.23/4
y = -2.06 (approximately)

Therefore, the solution to the system of equations is (10.59, -2.06), which is not one of the answer choices provided.