Solve the system of two equations using elimination with multiplication.

Question

4x - 6y = -48
-2x + 4y = 30

A) (3,9)
B) (-3,6)
C) (-33,-9)
D) (-21,-6)

Answer 1

First, let's multiply the second equation by 2 so that the x coefficients will be opposites:

4x - 6y = -48
-4x + 8y = 60

Now add the two equations together:

2y = 12
y = 6

Now we can substitute the value of y back into one of the original equations:

4x - 6(6) = -48
4x - 36 = -48
4x = -12
x = -3

Therefore, the solution to the system of equations is (-3, 6), which corresponds to answer choice B.