Question

Use the table to answer the question.

Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?

(1 point)
Responses

300
300

100
100

200
200

50

Answer 1

u sure

Answer 2

200

To find the estimated difference in the expected number of white and red balls in Bowl B, we first need to calculate the expected number of white balls in Bowl B. Since Clark repeatedly selected a ball from both bowls, the proportion of white balls selected from Bowl B is 60/(60+40) = 0.6.

If there are 500 balls in Bowl B, the estimated number of white balls in Bowl B is 0.6 * 500 = 300.

Similarly, the estimated number of red balls in Bowl B is 0.4 * 500 = 200.

The estimated difference in the expected number of white and red balls in Bowl B is 300 - 200 = 100.

Therefore, the answer is 100.

Answer 3

Apologies for the mistake in my previous response. Let me correct that.

If the proportions of white and red balls selected from Bowl B are 60/100 and 40/100 respectively. So, the expected number of white balls in Bowl B is 60/100 * 500 = 300 and the expected number of red balls is 40/100 * 500 = 200.

The estimated difference in the expected number of white and red balls in Bowl B is 300 - 200 = 100.

Therefore, the correct answer is: 100.