Question
My brain refuses to wrap around titration. Problem: Given 150.0 mL of a 1.05 M HCl solution, how many milliliters of a 2.50 M Al(OH)3 solution are required to neutralize the HCl?
I think the balanced formula is 3HCl + Al(OH)3 - AlCl +3H20 but that's as far as I get.
I think the balanced formula is 3HCl + Al(OH)3 - AlCl +3H20 but that's as far as I get.