Y=2x+4 and 2x+y=8

Answer 1

To find the solution to this system of equations, we can first solve for y in the second equation and then substitute it into the first equation.

2x + y = 8
y = 8 - 2x

Now, substitute y = 8 - 2x into the first equation:

Y = 2x + 4
8 - 2x = 2x + 4
8 = 4x + 4
4 = 4x
x = 1

Now, substitute x = 1 back into y = 8 - 2x to find y:

y = 8 - 2(1)
y = 8 - 2
y = 6

Therefore, the solution to the system of equations is x = 1 and y = 6.